Integrand size = 33, antiderivative size = 583 \[ \int \frac {\sec ^{\frac {9}{2}}(c+d x) (A+B \sec (c+d x))}{(a+b \sec (c+d x))^3} \, dx=-\frac {\left (15 a^4 A b-29 a^2 A b^3+8 A b^5-35 a^5 B+65 a^3 b^2 B-24 a b^4 B\right ) \sqrt {\cos (c+d x)} E\left (\left .\frac {1}{2} (c+d x)\right |2\right ) \sqrt {\sec (c+d x)}}{4 b^4 \left (a^2-b^2\right )^2 d}-\frac {\left (15 a^3 A b-33 a A b^3-35 a^4 B+61 a^2 b^2 B-8 b^4 B\right ) \sqrt {\cos (c+d x)} \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),2\right ) \sqrt {\sec (c+d x)}}{12 b^3 \left (a^2-b^2\right )^2 d}-\frac {a \left (15 a^4 A b-38 a^2 A b^3+35 A b^5-35 a^5 B+86 a^3 b^2 B-63 a b^4 B\right ) \sqrt {\cos (c+d x)} \operatorname {EllipticPi}\left (\frac {2 a}{a+b},\frac {1}{2} (c+d x),2\right ) \sqrt {\sec (c+d x)}}{4 (a-b)^2 b^4 (a+b)^3 d}+\frac {\left (15 a^4 A b-29 a^2 A b^3+8 A b^5-35 a^5 B+65 a^3 b^2 B-24 a b^4 B\right ) \sqrt {\sec (c+d x)} \sin (c+d x)}{4 b^4 \left (a^2-b^2\right )^2 d}-\frac {\left (15 a^3 A b-33 a A b^3-35 a^4 B+61 a^2 b^2 B-8 b^4 B\right ) \sec ^{\frac {3}{2}}(c+d x) \sin (c+d x)}{12 b^3 \left (a^2-b^2\right )^2 d}+\frac {a (A b-a B) \sec ^{\frac {7}{2}}(c+d x) \sin (c+d x)}{2 b \left (a^2-b^2\right ) d (a+b \sec (c+d x))^2}+\frac {a \left (3 a^2 A b-9 A b^3-7 a^3 B+13 a b^2 B\right ) \sec ^{\frac {5}{2}}(c+d x) \sin (c+d x)}{4 b^2 \left (a^2-b^2\right )^2 d (a+b \sec (c+d x))} \]
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Time = 2.14 (sec) , antiderivative size = 583, normalized size of antiderivative = 1.00, number of steps used = 12, number of rules used = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.303, Rules used = {4114, 4183, 4187, 4191, 3934, 2884, 3872, 3856, 2719, 2720} \[ \int \frac {\sec ^{\frac {9}{2}}(c+d x) (A+B \sec (c+d x))}{(a+b \sec (c+d x))^3} \, dx=\frac {a (A b-a B) \sin (c+d x) \sec ^{\frac {7}{2}}(c+d x)}{2 b d \left (a^2-b^2\right ) (a+b \sec (c+d x))^2}+\frac {a \left (-7 a^3 B+3 a^2 A b+13 a b^2 B-9 A b^3\right ) \sin (c+d x) \sec ^{\frac {5}{2}}(c+d x)}{4 b^2 d \left (a^2-b^2\right )^2 (a+b \sec (c+d x))}-\frac {\left (-35 a^4 B+15 a^3 A b+61 a^2 b^2 B-33 a A b^3-8 b^4 B\right ) \sin (c+d x) \sec ^{\frac {3}{2}}(c+d x)}{12 b^3 d \left (a^2-b^2\right )^2}-\frac {\left (-35 a^4 B+15 a^3 A b+61 a^2 b^2 B-33 a A b^3-8 b^4 B\right ) \sqrt {\cos (c+d x)} \sqrt {\sec (c+d x)} \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),2\right )}{12 b^3 d \left (a^2-b^2\right )^2}+\frac {\left (-35 a^5 B+15 a^4 A b+65 a^3 b^2 B-29 a^2 A b^3-24 a b^4 B+8 A b^5\right ) \sin (c+d x) \sqrt {\sec (c+d x)}}{4 b^4 d \left (a^2-b^2\right )^2}-\frac {\left (-35 a^5 B+15 a^4 A b+65 a^3 b^2 B-29 a^2 A b^3-24 a b^4 B+8 A b^5\right ) \sqrt {\cos (c+d x)} \sqrt {\sec (c+d x)} E\left (\left .\frac {1}{2} (c+d x)\right |2\right )}{4 b^4 d \left (a^2-b^2\right )^2}-\frac {a \left (-35 a^5 B+15 a^4 A b+86 a^3 b^2 B-38 a^2 A b^3-63 a b^4 B+35 A b^5\right ) \sqrt {\cos (c+d x)} \sqrt {\sec (c+d x)} \operatorname {EllipticPi}\left (\frac {2 a}{a+b},\frac {1}{2} (c+d x),2\right )}{4 b^4 d (a-b)^2 (a+b)^3} \]
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Rule 2719
Rule 2720
Rule 2884
Rule 3856
Rule 3872
Rule 3934
Rule 4114
Rule 4183
Rule 4187
Rule 4191
Rubi steps \begin{align*} \text {integral}& = \frac {a (A b-a B) \sec ^{\frac {7}{2}}(c+d x) \sin (c+d x)}{2 b \left (a^2-b^2\right ) d (a+b \sec (c+d x))^2}+\frac {\int \frac {\sec ^{\frac {5}{2}}(c+d x) \left (\frac {5}{2} a (A b-a B)-2 b (A b-a B) \sec (c+d x)-\frac {1}{2} \left (3 a A b-7 a^2 B+4 b^2 B\right ) \sec ^2(c+d x)\right )}{(a+b \sec (c+d x))^2} \, dx}{2 b \left (a^2-b^2\right )} \\ & = \frac {a (A b-a B) \sec ^{\frac {7}{2}}(c+d x) \sin (c+d x)}{2 b \left (a^2-b^2\right ) d (a+b \sec (c+d x))^2}+\frac {a \left (3 a^2 A b-9 A b^3-7 a^3 B+13 a b^2 B\right ) \sec ^{\frac {5}{2}}(c+d x) \sin (c+d x)}{4 b^2 \left (a^2-b^2\right )^2 d (a+b \sec (c+d x))}-\frac {\int \frac {\sec ^{\frac {3}{2}}(c+d x) \left (-\frac {3}{4} a \left (3 a^2 A b-9 A b^3-7 a^3 B+13 a b^2 B\right )-b \left (a^2 A b+2 A b^3+a^3 B-4 a b^2 B\right ) \sec (c+d x)+\frac {1}{4} \left (15 a^3 A b-33 a A b^3-35 a^4 B+61 a^2 b^2 B-8 b^4 B\right ) \sec ^2(c+d x)\right )}{a+b \sec (c+d x)} \, dx}{2 b^2 \left (a^2-b^2\right )^2} \\ & = -\frac {\left (15 a^3 A b-33 a A b^3-35 a^4 B+61 a^2 b^2 B-8 b^4 B\right ) \sec ^{\frac {3}{2}}(c+d x) \sin (c+d x)}{12 b^3 \left (a^2-b^2\right )^2 d}+\frac {a (A b-a B) \sec ^{\frac {7}{2}}(c+d x) \sin (c+d x)}{2 b \left (a^2-b^2\right ) d (a+b \sec (c+d x))^2}+\frac {a \left (3 a^2 A b-9 A b^3-7 a^3 B+13 a b^2 B\right ) \sec ^{\frac {5}{2}}(c+d x) \sin (c+d x)}{4 b^2 \left (a^2-b^2\right )^2 d (a+b \sec (c+d x))}-\frac {\int \frac {\sqrt {\sec (c+d x)} \left (\frac {1}{8} a \left (15 a^3 A b-33 a A b^3-35 a^4 B+61 a^2 b^2 B-8 b^4 B\right )-\frac {1}{2} b \left (3 a^3 A b-12 a A b^3-7 a^4 B+14 a^2 b^2 B+2 b^4 B\right ) \sec (c+d x)-\frac {3}{8} \left (15 a^4 A b-29 a^2 A b^3+8 A b^5-35 a^5 B+65 a^3 b^2 B-24 a b^4 B\right ) \sec ^2(c+d x)\right )}{a+b \sec (c+d x)} \, dx}{3 b^3 \left (a^2-b^2\right )^2} \\ & = \frac {\left (15 a^4 A b-29 a^2 A b^3+8 A b^5-35 a^5 B+65 a^3 b^2 B-24 a b^4 B\right ) \sqrt {\sec (c+d x)} \sin (c+d x)}{4 b^4 \left (a^2-b^2\right )^2 d}-\frac {\left (15 a^3 A b-33 a A b^3-35 a^4 B+61 a^2 b^2 B-8 b^4 B\right ) \sec ^{\frac {3}{2}}(c+d x) \sin (c+d x)}{12 b^3 \left (a^2-b^2\right )^2 d}+\frac {a (A b-a B) \sec ^{\frac {7}{2}}(c+d x) \sin (c+d x)}{2 b \left (a^2-b^2\right ) d (a+b \sec (c+d x))^2}+\frac {a \left (3 a^2 A b-9 A b^3-7 a^3 B+13 a b^2 B\right ) \sec ^{\frac {5}{2}}(c+d x) \sin (c+d x)}{4 b^2 \left (a^2-b^2\right )^2 d (a+b \sec (c+d x))}-\frac {2 \int \frac {\frac {3}{16} a \left (15 a^4 A b-29 a^2 A b^3+8 A b^5-35 a^5 B+65 a^3 b^2 B-24 a b^4 B\right )+\frac {1}{4} b \left (15 a^4 A b-30 a^2 A b^3+6 A b^5-35 a^5 B+64 a^3 b^2 B-20 a b^4 B\right ) \sec (c+d x)+\frac {1}{16} \left (45 a^5 A b-99 a^3 A b^3+72 a A b^5-105 a^6 B+223 a^4 b^2 B-128 a^2 b^4 B-8 b^6 B\right ) \sec ^2(c+d x)}{\sqrt {\sec (c+d x)} (a+b \sec (c+d x))} \, dx}{3 b^4 \left (a^2-b^2\right )^2} \\ & = \frac {\left (15 a^4 A b-29 a^2 A b^3+8 A b^5-35 a^5 B+65 a^3 b^2 B-24 a b^4 B\right ) \sqrt {\sec (c+d x)} \sin (c+d x)}{4 b^4 \left (a^2-b^2\right )^2 d}-\frac {\left (15 a^3 A b-33 a A b^3-35 a^4 B+61 a^2 b^2 B-8 b^4 B\right ) \sec ^{\frac {3}{2}}(c+d x) \sin (c+d x)}{12 b^3 \left (a^2-b^2\right )^2 d}+\frac {a (A b-a B) \sec ^{\frac {7}{2}}(c+d x) \sin (c+d x)}{2 b \left (a^2-b^2\right ) d (a+b \sec (c+d x))^2}+\frac {a \left (3 a^2 A b-9 A b^3-7 a^3 B+13 a b^2 B\right ) \sec ^{\frac {5}{2}}(c+d x) \sin (c+d x)}{4 b^2 \left (a^2-b^2\right )^2 d (a+b \sec (c+d x))}-\frac {2 \int \frac {\frac {3}{16} a^2 \left (15 a^4 A b-29 a^2 A b^3+8 A b^5-35 a^5 B+65 a^3 b^2 B-24 a b^4 B\right )-\left (\frac {3}{16} a b \left (15 a^4 A b-29 a^2 A b^3+8 A b^5-35 a^5 B+65 a^3 b^2 B-24 a b^4 B\right )-\frac {1}{4} a b \left (15 a^4 A b-30 a^2 A b^3+6 A b^5-35 a^5 B+64 a^3 b^2 B-20 a b^4 B\right )\right ) \sec (c+d x)}{\sqrt {\sec (c+d x)}} \, dx}{3 a^2 b^4 \left (a^2-b^2\right )^2}-\frac {\left (a \left (15 a^4 A b-38 a^2 A b^3+35 A b^5-35 a^5 B+86 a^3 b^2 B-63 a b^4 B\right )\right ) \int \frac {\sec ^{\frac {3}{2}}(c+d x)}{a+b \sec (c+d x)} \, dx}{8 b^4 \left (a^2-b^2\right )^2} \\ & = \frac {\left (15 a^4 A b-29 a^2 A b^3+8 A b^5-35 a^5 B+65 a^3 b^2 B-24 a b^4 B\right ) \sqrt {\sec (c+d x)} \sin (c+d x)}{4 b^4 \left (a^2-b^2\right )^2 d}-\frac {\left (15 a^3 A b-33 a A b^3-35 a^4 B+61 a^2 b^2 B-8 b^4 B\right ) \sec ^{\frac {3}{2}}(c+d x) \sin (c+d x)}{12 b^3 \left (a^2-b^2\right )^2 d}+\frac {a (A b-a B) \sec ^{\frac {7}{2}}(c+d x) \sin (c+d x)}{2 b \left (a^2-b^2\right ) d (a+b \sec (c+d x))^2}+\frac {a \left (3 a^2 A b-9 A b^3-7 a^3 B+13 a b^2 B\right ) \sec ^{\frac {5}{2}}(c+d x) \sin (c+d x)}{4 b^2 \left (a^2-b^2\right )^2 d (a+b \sec (c+d x))}-\frac {\left (15 a^3 A b-33 a A b^3-35 a^4 B+61 a^2 b^2 B-8 b^4 B\right ) \int \sqrt {\sec (c+d x)} \, dx}{24 b^3 \left (a^2-b^2\right )^2}-\frac {\left (15 a^4 A b-29 a^2 A b^3+8 A b^5-35 a^5 B+65 a^3 b^2 B-24 a b^4 B\right ) \int \frac {1}{\sqrt {\sec (c+d x)}} \, dx}{8 b^4 \left (a^2-b^2\right )^2}-\frac {\left (a \left (15 a^4 A b-38 a^2 A b^3+35 A b^5-35 a^5 B+86 a^3 b^2 B-63 a b^4 B\right ) \sqrt {\cos (c+d x)} \sqrt {\sec (c+d x)}\right ) \int \frac {1}{\sqrt {\cos (c+d x)} (b+a \cos (c+d x))} \, dx}{8 b^4 \left (a^2-b^2\right )^2} \\ & = -\frac {a \left (15 a^4 A b-38 a^2 A b^3+35 A b^5-35 a^5 B+86 a^3 b^2 B-63 a b^4 B\right ) \sqrt {\cos (c+d x)} \operatorname {EllipticPi}\left (\frac {2 a}{a+b},\frac {1}{2} (c+d x),2\right ) \sqrt {\sec (c+d x)}}{4 (a-b)^2 b^4 (a+b)^3 d}+\frac {\left (15 a^4 A b-29 a^2 A b^3+8 A b^5-35 a^5 B+65 a^3 b^2 B-24 a b^4 B\right ) \sqrt {\sec (c+d x)} \sin (c+d x)}{4 b^4 \left (a^2-b^2\right )^2 d}-\frac {\left (15 a^3 A b-33 a A b^3-35 a^4 B+61 a^2 b^2 B-8 b^4 B\right ) \sec ^{\frac {3}{2}}(c+d x) \sin (c+d x)}{12 b^3 \left (a^2-b^2\right )^2 d}+\frac {a (A b-a B) \sec ^{\frac {7}{2}}(c+d x) \sin (c+d x)}{2 b \left (a^2-b^2\right ) d (a+b \sec (c+d x))^2}+\frac {a \left (3 a^2 A b-9 A b^3-7 a^3 B+13 a b^2 B\right ) \sec ^{\frac {5}{2}}(c+d x) \sin (c+d x)}{4 b^2 \left (a^2-b^2\right )^2 d (a+b \sec (c+d x))}-\frac {\left (\left (15 a^3 A b-33 a A b^3-35 a^4 B+61 a^2 b^2 B-8 b^4 B\right ) \sqrt {\cos (c+d x)} \sqrt {\sec (c+d x)}\right ) \int \frac {1}{\sqrt {\cos (c+d x)}} \, dx}{24 b^3 \left (a^2-b^2\right )^2}-\frac {\left (\left (15 a^4 A b-29 a^2 A b^3+8 A b^5-35 a^5 B+65 a^3 b^2 B-24 a b^4 B\right ) \sqrt {\cos (c+d x)} \sqrt {\sec (c+d x)}\right ) \int \sqrt {\cos (c+d x)} \, dx}{8 b^4 \left (a^2-b^2\right )^2} \\ & = -\frac {\left (15 a^4 A b-29 a^2 A b^3+8 A b^5-35 a^5 B+65 a^3 b^2 B-24 a b^4 B\right ) \sqrt {\cos (c+d x)} E\left (\left .\frac {1}{2} (c+d x)\right |2\right ) \sqrt {\sec (c+d x)}}{4 b^4 \left (a^2-b^2\right )^2 d}-\frac {\left (15 a^3 A b-33 a A b^3-35 a^4 B+61 a^2 b^2 B-8 b^4 B\right ) \sqrt {\cos (c+d x)} \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),2\right ) \sqrt {\sec (c+d x)}}{12 b^3 \left (a^2-b^2\right )^2 d}-\frac {a \left (15 a^4 A b-38 a^2 A b^3+35 A b^5-35 a^5 B+86 a^3 b^2 B-63 a b^4 B\right ) \sqrt {\cos (c+d x)} \operatorname {EllipticPi}\left (\frac {2 a}{a+b},\frac {1}{2} (c+d x),2\right ) \sqrt {\sec (c+d x)}}{4 (a-b)^2 b^4 (a+b)^3 d}+\frac {\left (15 a^4 A b-29 a^2 A b^3+8 A b^5-35 a^5 B+65 a^3 b^2 B-24 a b^4 B\right ) \sqrt {\sec (c+d x)} \sin (c+d x)}{4 b^4 \left (a^2-b^2\right )^2 d}-\frac {\left (15 a^3 A b-33 a A b^3-35 a^4 B+61 a^2 b^2 B-8 b^4 B\right ) \sec ^{\frac {3}{2}}(c+d x) \sin (c+d x)}{12 b^3 \left (a^2-b^2\right )^2 d}+\frac {a (A b-a B) \sec ^{\frac {7}{2}}(c+d x) \sin (c+d x)}{2 b \left (a^2-b^2\right ) d (a+b \sec (c+d x))^2}+\frac {a \left (3 a^2 A b-9 A b^3-7 a^3 B+13 a b^2 B\right ) \sec ^{\frac {5}{2}}(c+d x) \sin (c+d x)}{4 b^2 \left (a^2-b^2\right )^2 d (a+b \sec (c+d x))} \\ \end{align*}
Time = 7.91 (sec) , antiderivative size = 897, normalized size of antiderivative = 1.54 \[ \int \frac {\sec ^{\frac {9}{2}}(c+d x) (A+B \sec (c+d x))}{(a+b \sec (c+d x))^3} \, dx=\frac {\frac {2 \left (-135 a^5 A b+285 a^3 A b^3-168 a A b^5+315 a^6 B-641 a^4 b^2 B+328 a^2 b^4 B+16 b^6 B\right ) \cos ^2(c+d x) \left (\operatorname {EllipticF}\left (\arcsin \left (\sqrt {\sec (c+d x)}\right ),-1\right )-\operatorname {EllipticPi}\left (-\frac {b}{a},\arcsin \left (\sqrt {\sec (c+d x)}\right ),-1\right )\right ) (a+b \sec (c+d x)) \sqrt {1-\sec ^2(c+d x)} \sin (c+d x)}{b (b+a \cos (c+d x)) \left (1-\cos ^2(c+d x)\right )}+\frac {2 \left (-120 a^4 A b^2+240 a^2 A b^4-48 A b^6+280 a^5 b B-512 a^3 b^3 B+160 a b^5 B\right ) \cos ^2(c+d x) \operatorname {EllipticPi}\left (-\frac {b}{a},\arcsin \left (\sqrt {\sec (c+d x)}\right ),-1\right ) (a+b \sec (c+d x)) \sqrt {1-\sec ^2(c+d x)} \sin (c+d x)}{a (b+a \cos (c+d x)) \left (1-\cos ^2(c+d x)\right )}+\frac {\left (-45 a^5 A b+87 a^3 A b^3-24 a A b^5+105 a^6 B-195 a^4 b^2 B+72 a^2 b^4 B\right ) \cos (2 (c+d x)) (a+b \sec (c+d x)) \left (-4 a b+4 a b \sec ^2(c+d x)-4 a b E\left (\left .\arcsin \left (\sqrt {\sec (c+d x)}\right )\right |-1\right ) \sqrt {\sec (c+d x)} \sqrt {1-\sec ^2(c+d x)}-2 a (a-2 b) \operatorname {EllipticF}\left (\arcsin \left (\sqrt {\sec (c+d x)}\right ),-1\right ) \sqrt {\sec (c+d x)} \sqrt {1-\sec ^2(c+d x)}+2 a^2 \operatorname {EllipticPi}\left (-\frac {b}{a},\arcsin \left (\sqrt {\sec (c+d x)}\right ),-1\right ) \sqrt {\sec (c+d x)} \sqrt {1-\sec ^2(c+d x)}-4 b^2 \operatorname {EllipticPi}\left (-\frac {b}{a},\arcsin \left (\sqrt {\sec (c+d x)}\right ),-1\right ) \sqrt {\sec (c+d x)} \sqrt {1-\sec ^2(c+d x)}\right ) \sin (c+d x)}{a^2 b (b+a \cos (c+d x)) \left (1-\cos ^2(c+d x)\right ) \sqrt {\sec (c+d x)} \left (2-\sec ^2(c+d x)\right )}}{48 (a-b)^2 b^4 (a+b)^2 d}+\frac {\sqrt {\sec (c+d x)} \left (\frac {\left (15 a^4 A b-29 a^2 A b^3+8 A b^5-35 a^5 B+65 a^3 b^2 B-24 a b^4 B\right ) \sin (c+d x)}{4 b^4 \left (-a^2+b^2\right )^2}+\frac {a^2 A b \sin (c+d x)-a^3 B \sin (c+d x)}{2 b^2 \left (-a^2+b^2\right ) (b+a \cos (c+d x))^2}+\frac {-5 a^4 A b \sin (c+d x)+11 a^2 A b^3 \sin (c+d x)+9 a^5 B \sin (c+d x)-15 a^3 b^2 B \sin (c+d x)}{4 b^3 \left (-a^2+b^2\right )^2 (b+a \cos (c+d x))}+\frac {2 B \tan (c+d x)}{3 b^3}\right )}{d} \]
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Leaf count of result is larger than twice the leaf count of optimal. \(2150\) vs. \(2(627)=1254\).
Time = 226.14 (sec) , antiderivative size = 2151, normalized size of antiderivative = 3.69
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Timed out. \[ \int \frac {\sec ^{\frac {9}{2}}(c+d x) (A+B \sec (c+d x))}{(a+b \sec (c+d x))^3} \, dx=\text {Timed out} \]
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Timed out. \[ \int \frac {\sec ^{\frac {9}{2}}(c+d x) (A+B \sec (c+d x))}{(a+b \sec (c+d x))^3} \, dx=\text {Timed out} \]
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Timed out. \[ \int \frac {\sec ^{\frac {9}{2}}(c+d x) (A+B \sec (c+d x))}{(a+b \sec (c+d x))^3} \, dx=\text {Timed out} \]
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\[ \int \frac {\sec ^{\frac {9}{2}}(c+d x) (A+B \sec (c+d x))}{(a+b \sec (c+d x))^3} \, dx=\int { \frac {{\left (B \sec \left (d x + c\right ) + A\right )} \sec \left (d x + c\right )^{\frac {9}{2}}}{{\left (b \sec \left (d x + c\right ) + a\right )}^{3}} \,d x } \]
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Timed out. \[ \int \frac {\sec ^{\frac {9}{2}}(c+d x) (A+B \sec (c+d x))}{(a+b \sec (c+d x))^3} \, dx=\int \frac {\left (A+\frac {B}{\cos \left (c+d\,x\right )}\right )\,{\left (\frac {1}{\cos \left (c+d\,x\right )}\right )}^{9/2}}{{\left (a+\frac {b}{\cos \left (c+d\,x\right )}\right )}^3} \,d x \]
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